The series ∑n=2∞xnn(lnn)2\sum_{n=2}^{\infty} \frac{x^n}{n(\ln n)^2}∑n=2∞n(lnn)2xn converges at which values of xxx?
∣x∣<1|x| < 1∣x∣<1 only
∣x∣≤1|x| \leq 1∣x∣≤1
x=1x = 1x=1 only
∣x∣<1|x| < 1∣x∣<1 and x=−1x = -1x=−1