The series ∑n=1∞(x−2)nn\sum_{n=1}^{\infty} \frac{(x-2)^n}{n}∑n=1∞n(x−2)n is centered at:
x=0x=0x=0
x=1x=1x=1
x=2x=2x=2
x=3x=3x=3