Ononot — The sequence an satisfies an = 4a{n-1} - 4a{n-2}. Given a0 =

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Recurrence Relationsmedium

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The sequence $a_n$ satisfies $a_n = 4a_{n-1} - 4a_{n-2}$ . Given $a_0 = 1$ and $a_1 = 4$ , calculate $a_2$ .