Divisibilityhard
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The prime factorization of n is 2^a × 3^b. For what values of (a,b) is n a perfect cube?
The prime factorization of n is 2^a × 3^b. For what values of (a,b) is n a perfect cube?
The prime factorization of n is 2^a × 3^b. For what values of (a,b) is n a perfect cube?