The parabola y=(x+2)2−5y = (x + 2)^2 - 5y=(x+2)2−5 has vertex at which location?
(−2,−5)(-2, -5)(−2,−5)
(2,−5)(2, -5)(2,−5)
(−2,5)(-2, 5)(−2,5)
(0,−5)(0, -5)(0,−5)