The Maclaurin series for ln(1+x)\ln(1+x)ln(1+x) is ∑n=1∞(−1)n+1xnn\sum_{n=1}^{\infty} \frac{(-1)^{n+1} x^n}{n}∑n=1∞n(−1)n+1xn with R=1R = 1R=1. Which series represents ln(1+2x)\ln(1+2x)ln(1+2x)?
∑n=1∞(−1)n+1(2x)nn\sum_{n=1}^{\infty} \frac{(-1)^{n+1} (2x)^n}{n}∑n=1∞n(−1)n+1(2x)n
∑n=1∞(−1)n+12nxnn\sum_{n=1}^{\infty} \frac{(-1)^{n+1} 2^n x^n}{n}∑n=1∞n(−1)n+12nxn
Both a and b are identical
The radius of convergence is R=1R = 1R=1