The Maclaurin series for arcsin(x)\arcsin(x)arcsin(x) has the form ∑n=0∞(2n)!4n(n!)2(2n+1)x2n+1\sum_{n=0}^{\infty} \frac{(2n)!}{4^n (n!)^2 (2n+1)} x^{2n+1}∑n=0∞4n(n!)2(2n+1)(2n)!x2n+1. What is its radius of convergence?
R=0R = 0R=0
R=1R = 1R=1
R=2R = 2R=2
R=∞R = \inftyR=∞