The integral ∫0∞dxx4+x2+1\int_0^{\infty} \frac{dx}{x^4+x^2+1}∫0∞x4+x2+1dx is equal to:
π23\frac{\pi}{2\sqrt{3}}23π
π3\frac{\pi}{3}3π
π3\frac{\pi}{\sqrt{3}}3π
π4\frac{\pi}{4}4π