The general solution to a recurrence is an=A⋅2n+B⋅3na_n = A \cdot 2^n + B \cdot 3^nan=A⋅2n+B⋅3n. Given a0=1a_0 = 1a0=1 and a1=5a_1 = 5a1=5, find A+BA + BA+B.
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