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Diophantine Equationseasy
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The fundamental solution to Pell's equation x2−2y2=1x^2 - 2y^2 = 1x2−2y2=1 is (x0,y0)=(3,2)(x_0, y_0) = (3, 2)(x0​,y0​)=(3,2). New solutions are generated by the recurrence: xn+1=3xn+4ynx_{n+1} = 3x_n + 4y_nxn+1​=3xn​+4yn​ and yn+1=2xn+3yny_{n+1} = 2x_n + 3y_nyn+1​=2xn​+3yn​. What is the next solution (x1,y1)(x_1, y_1)(x1​,y1​)?