The equation of the normal to the parabola y2=4xy^2 = 4xy2=4x at point (1,2)(1, 2)(1,2) is:
x+y=3x + y = 3x+y=3
x−y=−1x - y = -1x−y=−1
y=x+1y = x + 1y=x+1
x+y=1x + y = 1x+y=1