The equation of the line passing through (1,2)(1, 2)(1,2) and parallel to 2x−3y+5=02x-3y+5=02x−3y+5=0 is:
2x−3y+4=02x-3y+4=02x−3y+4=0
3x−2y+1=03x-2y+1=03x−2y+1=0
2x−3y−4=02x-3y-4=02x−3y−4=0
2x+3y−8=02x+3y-8=02x+3y−8=0