Infinite Serieshard
0:00.0

The dilogarithm function is defined as Li2(x)=n=1xnn2\operatorname{Li}_2(x) = \sum_{n=1}^{\infty} \frac{x^n}{n^2}. Using the identity Li2(x)+Li2(1x)=π26ln(x)ln(1x)\operatorname{Li}_2(x) + \operatorname{Li}_2(1-x) = \frac{\pi^2}{6} - \ln(x)\ln(1-x) for x(0,1)x \in (0, 1), evaluate the series n=11n22n\sum_{n=1}^{\infty} \frac{1}{n^2 2^n}.