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Recursionhard
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The Ackermann function satisfies: A(0,n)=n+1A(0, n) = n + 1A(0,n)=n+1, A(m,0)=A(m−1,1)A(m, 0) = A(m-1, 1)A(m,0)=A(m−1,1) for m>0m > 0m>0, and A(m,n)=A(m−1,A(m,n−1))A(m, n) = A(m-1, A(m, n-1))A(m,n)=A(m−1,A(m,n−1)) for m,n>0m,n > 0m,n>0. What is A(3,0)A(3, 0)A(3,0)?