Guest Session: 1 Question Remaining. Create Account to save progress.
Login
Conditional Probabilityhard
0:00.0

Suppose XXX and YYY are independent random variables where P(X=1)=pP(X=1)=pP(X=1)=p and P(Y=1)=qP(Y=1)=qP(Y=1)=q. We observe Z=X+YZ = X + YZ=X+Y. Given that Z=1Z=1Z=1, what is the probability P(X=1)P(X=1)P(X=1) in terms of ppp and qqq?