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Inferential Statisticshard
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Suppose we have a 2×22 \times 22×2 contingency table with counts n11=1,n12=1,n21=1,n22=1n_{11}=1, n_{12}=1, n_{21}=1, n_{22}=1n11​=1,n12​=1,n21​=1,n22​=1. Why is the standard Chi-squared test for independence inappropriate here?