Subtract: 4x−3x+1\dfrac{4}{x} - \dfrac{3}{x + 1}x4−x+13.
x+4x(x+1)\dfrac{x + 4}{x(x+1)}x(x+1)x+4
7x+4x(x+1)\dfrac{7x + 4}{x(x+1)}x(x+1)7x+4
x−4x(x+1)\dfrac{x - 4}{x(x+1)}x(x+1)x−4
1x(x+1)\dfrac{1}{x(x+1)}x(x+1)1