Subtract: 2xx2−9−1x+3\dfrac{2x}{x^2 - 9} - \dfrac{1}{x + 3}x2−92x−x+31.
x+3(x−3)(x+3)\dfrac{x + 3}{(x-3)(x+3)}(x−3)(x+3)x+3
x−3(x−3)(x+3)\dfrac{x - 3}{(x-3)(x+3)}(x−3)(x+3)x−3
2x−x+3x2−9\dfrac{2x - x + 3}{x^2-9}x2−92x−x+3
x+3x2−9\dfrac{x + 3}{x^2 - 9}x2−9x+3