Solve y′=y3y' = y^3y′=y3.
−1/(2y2)=x+C-1/(2y^2) = x + C−1/(2y2)=x+C
y=x1/3y = x^{1/3}y=x1/3
y2=2x+Cy^2 = 2x + Cy2=2x+C
None