Solve y′=y2y' = y^2y′=y2.
y=−1/(x+C)y = -1/(x+C)y=−1/(x+C)
y=x3/3+Cy = x^3/3 + Cy=x3/3+C
y=e2xy = e^{2x}y=e2x
y=1/xy = 1/xy=1/x