Solve y′′−25y=0y'' - 25y = 0y′′−25y=0.
y=C1e5x+C2e−5xy = C_1 e^{5x} + C_2 e^{-5x}y=C1e5x+C2e−5x
y=C1cos5x+C2sin5xy = C_1 \cos 5x + C_2 \sin 5xy=C1cos5x+C2sin5x
y=(C1+C2x)e5xy = (C_1 + C_2 x) e^{5x}y=(C1+C2x)e5x
None