Solve y′=1/(x+1)y' = 1/(x+1)y′=1/(x+1).
y=ln∣x+1∣+Cy = \ln|x+1| + Cy=ln∣x+1∣+C
y=ex+1+Cy = e^{x+1} + Cy=ex+1+C
y=x+1y = x+1y=x+1
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