Solve y′=1/xy' = 1/xy′=1/x.
y=ln∣x∣+Cy = \ln|x| + Cy=ln∣x∣+C
y=ex+Cy = e^x + Cy=ex+C
y=−1/x2+Cy = -1/x^2 + Cy=−1/x2+C
y=xy = xy=x