Solve the system of congruences: x≡2(mod3)x \equiv 2 \pmod 3x≡2(mod3) and x≡3(mod5)x \equiv 3 \pmod 5x≡3(mod5).
x≡8(mod15)x \equiv 8 \pmod{15}x≡8(mod15)
x≡11(mod15)x \equiv 11 \pmod{15}x≡11(mod15)
x≡13(mod15)x \equiv 13 \pmod{15}x≡13(mod15)
x≡5(mod15)x \equiv 5 \pmod{15}x≡5(mod15)