Solve the separable equation y′=y2y' = y^2y′=y2.
y=−1/(x+C)y = -1 / (x + C)y=−1/(x+C)
y=ex+Cy = e^{x+C}y=ex+C
y=x3/3+Cy = x^3/3 + Cy=x3/3+C
y=1/xy = 1/xy=1/x