Solve the linear congruence 2x≡5(mod9)2x \equiv 5 \pmod 92x≡5(mod9).
x≡7(mod9)x \equiv 7 \pmod 9x≡7(mod9)
x≡2(mod9)x \equiv 2 \pmod 9x≡2(mod9)
x≡5(mod9)x \equiv 5 \pmod 9x≡5(mod9)
No solution