Solve the initial value problem y′=exy' = e^xy′=ex, y(0)=2y(0) = 2y(0)=2.
y=ex+1y = e^x + 1y=ex+1
y=ex+2y = e^x + 2y=ex+2
y=exy = e^xy=ex
y=ex−1y = e^x - 1y=ex−1