Solve ∣z∣2−3∣z∣+2=0|z|^2 - 3|z| + 2 = 0∣z∣2−3∣z∣+2=0 and find all possible values of ∣z∣|z|∣z∣.
∣z∣=1|z| = 1∣z∣=1 or ∣z∣=2|z| = 2∣z∣=2
∣z∣=2|z| = 2∣z∣=2 or ∣z∣=3|z| = 3∣z∣=3
∣z∣=1|z| = 1∣z∣=1 only
∣z∣=3|z| = 3∣z∣=3 or ∣z∣=4|z| = 4∣z∣=4