Ononot — Solve y' = \frac{x^2+1}{y} with y(0) = 2. What is y^2 at x =

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Differential Equationsmedium

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Solve $y' = \frac{x^2+1}{y}$ with $y(0) = 2$ . What is $y^2$ at $x = \sqrt{3}$ ?