Solve y′=2x(1+y2)y' = 2x(1+y^2)y′=2x(1+y2) with y(0)=0y(0)=0y(0)=0.
y=tan(x2)y = \tan(x^2)y=tan(x2)
y=tan2(x)y = \tan^2(x)y=tan2(x)
y=arctan(x2)y = \arctan(x^2)y=arctan(x2)
y=x2y = x^2y=x2