Solve: x3−4x2+x+6>0x^3 - 4x^2 + x + 6 > 0x3−4x2+x+6>0.
(−1,2)∪(3,∞)(-1, 2) \cup (3, \infty)(−1,2)∪(3,∞)
(−∞,−1)∪(2,3)(-\infty, -1) \cup (2, 3)(−∞,−1)∪(2,3)
(−1,3)(-1, 3)(−1,3)
(2,∞)(2, \infty)(2,∞)