Solve: x3−4x≥0x^3 - 4x \geq 0x3−4x≥0.
[−2,0]∪[2,∞)[-2, 0] \cup [2, \infty)[−2,0]∪[2,∞)
[0,2][0, 2][0,2]
(−∞,−2]∪[0,2](-\infty, -2] \cup [0, 2](−∞,−2]∪[0,2]
[−2,2][-2, 2][−2,2]