Solve: x2−x−12≤0x^2 - x - 12 \leq 0x2−x−12≤0.
x≤−3x \leq -3x≤−3 or x≥4x \geq 4x≥4
−3≤x≤4-3 \leq x \leq 4−3≤x≤4
x≤3x \leq 3x≤3 or x≥4x \geq 4x≥4
x≤−4x \leq -4x≤−4 or x≥3x \geq 3x≥3