Solve: x2−5x+6≥0x^2 - 5x + 6 \geq 0x2−5x+6≥0
x≤2x \leq 2x≤2 or x≥3x \geq 3x≥3
2≤x≤32 \leq x \leq 32≤x≤3
x∈(−∞,2]∪[3,∞)x \in (-\infty, 2] \cup [3, \infty)x∈(−∞,2]∪[3,∞)
(x−2)(x−3)≥0(x - 2)(x - 3) \geq 0(x−2)(x−3)≥0