Solve: x2−5x+4≤0x^2 - 5x + 4 \leq 0x2−5x+4≤0.
1≤x≤41 \leq x \leq 41≤x≤4
x≤1x \leq 1x≤1 or x≥4x \geq 4x≥4
x≤4x \leq 4x≤4
x≥1x \geq 1x≥1