Solve: x2−2x−3>0x^2 - 2x - 3 > 0x2−2x−3>0
x<−1x < -1x<−1 or x>3x > 3x>3
−1<x<3-1 < x < 3−1<x<3
x∈(−∞,−1)∪(3,∞)x \in (-\infty, -1) \cup (3, \infty)x∈(−∞,−1)∪(3,∞)
Parabola opens upward with roots at x=−1,3x = -1, 3x=−1,3