Solve x≡1(mod2)x \equiv 1 \pmod{2}x≡1(mod2), x≡2(mod3)x \equiv 2 \pmod{3}x≡2(mod3), x≡3(mod5)x \equiv 3 \pmod{5}x≡3(mod5).
x≡8(mod30)x \equiv 8 \pmod{30}x≡8(mod30)
x≡23(mod30)x \equiv 23 \pmod{30}x≡23(mod30)
x≡53(mod30)x \equiv 53 \pmod{30}x≡53(mod30)
x≡13(mod30)x \equiv 13 \pmod{30}x≡13(mod30)