Solve: ∣x+1∣−2>3|x + 1| - 2 > 3∣x+1∣−2>3
x>4x > 4x>4 or x<−6x < -6x<−6
−6<x<4-6 < x < 4−6<x<4
x∈Rx \in \mathbb{R}x∈R (all reals)
−6≤x≤4-6 \leq x \leq 4−6≤x≤4