Solve the system x≡1(mod3)x \equiv 1 \pmod{3}x≡1(mod3) and x≡2(mod4)x \equiv 2 \pmod{4}x≡2(mod4).
x≡7(mod12)x \equiv 7 \pmod{12}x≡7(mod12)
x≡10(mod12)x \equiv 10 \pmod{12}x≡10(mod12)
x≡4(mod12)x \equiv 4 \pmod{12}x≡4(mod12)
x≡1(mod12)x \equiv 1 \pmod{12}x≡1(mod12)