Solve the system: x≡1(mod2)x \equiv 1 \pmod{2}x≡1(mod2), x≡0(mod3)x \equiv 0 \pmod{3}x≡0(mod3), and x≡1(mod5)x \equiv 1 \pmod{5}x≡1(mod5).
666
111111
151515
212121