Solve the system {∣2x−3∣=y3x+2y=8\begin{cases} |2x-3| = y \\ 3x + 2y = 8 \end{cases}{∣2x−3∣=y3x+2y=8. How many solution pairs (x,y)(x, y)(x,y) exist?
0 solutions
1 solution
2 solutions
Infinitely many solutions