Solve the separable equation y′=xy2y' = \frac{x}{y^2}y′=y2x with y(0)=1y(0) = 1y(0)=1.
y=(32x2+1)1\slash3y = (\frac{3}{2}x^2 + 1)^{1\slash 3}y=(23x2+1)1\slash3
y=(12x2+1)1\slash3y = (\frac{1}{2}x^2 + 1)^{1\slash 3}y=(21x2+1)1\slash3
y=(32x2+1)2\slash3y = (\frac{3}{2}x^2 + 1)^{2\slash 3}y=(23x2+1)2\slash3
y=(34x2+1)1\slash3y = (\frac{3}{4}x^2 + 1)^{1\slash 3}y=(43x2+1)1\slash3