Solve the separable equation y′=xyy' = \frac{x}{y}y′=yx with y(0)=1y(0) = 1y(0)=1. What is y(x)y(x)y(x)?
y=x2+1y = \sqrt{x^2+1}y=x2+1
y=x2+1y = x^2+1y=x2+1
y=12x2+1y = \frac{1}{2}x^2+1y=21x2+1
y=ex2y = e^{x^2}y=ex2