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Recursionhard
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Solve the recurrence relation an−6an−1+9an−2=0a_n - 6a_{n-1} + 9a_{n-2} = 0an​−6an−1​+9an−2​=0 with initial conditions a0=1a_0 = 1a0​=1 and a1=9a_1 = 9a1​=9. What is a3a_3a3​?