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Recursionhard
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Solve the recurrence an=4an−1−4an−2a_n = 4a_{n-1} - 4a_{n-2}an​=4an−1​−4an−2​ with a0=1,a1=3a_0 = 1, a_1 = 3a0​=1,a1​=3. Find a2a_2a2​.