Solve the recurrence an=4an−1−4an−2a_n = 4a_{n-1} - 4a_{n-2}an=4an−1−4an−2 with a0=1,a1=3a_0 = 1, a_1 = 3a0=1,a1=3. Find a2a_2a2.
888
101010
121212
141414