Solve the rational inequality: (3x−1)(x+2)x2−4≤0\frac{(3x - 1)(x + 2)}{x^2 - 4} \leq 0x2−4(3x−1)(x+2)≤0
Which is the solution set?
(−∞,−2)∪[13,2)\left(-\infty, -2\right) \cup \left[\frac{1}{3}, 2\right)(−∞,−2)∪[31,2)
[−2,13]∪(2,∞)\left[-2, \frac{1}{3}\right] \cup (2, \infty)[−2,31]∪(2,∞)
(−2,13]∪[2,∞)\left(-2, \frac{1}{3}\right] \cup [2, \infty)(−2,31]∪[2,∞)
(−∞,−2)∪[13,2]∪(2,∞)\left(-\infty, -2\right) \cup \left[\frac{1}{3}, 2\right] \cup (2, \infty)(−∞,−2)∪[31,2]∪(2,∞)