Solve the rational equation: 3x+1+2x=1\frac{3}{x+1} + \frac{2}{x} = 1x+13+x2=1. Which value(s) satisfy this equation?
x=2+6x = 2 + \sqrt{6}x=2+6 only
x=2−6x = 2 - \sqrt{6}x=2−6 only
x=2+6x = 2 + \sqrt{6}x=2+6 and x=2−6x = 2 - \sqrt{6}x=2−6
No real solutions