Solve the linear congruence: 3x≡7(mod11)3x \equiv 7 \pmod{11}3x≡7(mod11)
x≡2(mod11)x \equiv 2 \pmod{11}x≡2(mod11)
x≡4(mod11)x \equiv 4 \pmod{11}x≡4(mod11)
x≡6(mod11)x \equiv 6 \pmod{11}x≡6(mod11)
x≡9(mod11)x \equiv 9 \pmod{11}x≡9(mod11)