Solve the initial value problem y′=−5yy' = -5yy′=−5y with y(0)=2y(0) = 2y(0)=2. What is the value of y(t)y(t)y(t) at t=ln(2)t = \ln(2)t=ln(2)?
0.250.250.25
0.50.50.5
111
222