Solve the inequality: x−3x+1≥0\frac{x - 3}{x + 1} \ge 0x+1x−3≥0.
x>3x > 3x>3
x≥3x \ge 3x≥3 or x<−1x < -1x<−1
x≤−1x \le -1x≤−1
−1<x≤3-1 < x \le 3−1<x≤3